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Author
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Topic: Vertical unit in a power spectral density plot.
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Nick Weis
unregistered
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posted 08-19-1999 11:03 AM
 
I'm not sure I understand your statement "..at 4nV/Root Hz (or it could be stated as 16 nV^2/Hz)." Are these two items equivalent? Over the audio band you indicated, 100Hz to 10KHz, using 4nV/Root Hz, I calulated the same rms number as you - 0.4 microvolts, rms. However, if I use 16 nV^2/Hz, I calculate 0.0126 volts, rms. I used SQRT(16nV * (10000-100)). Can you help me?
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R. Peterson
unregistered
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posted 09-26-1997 10:19 AM
From: robpeterson@iname.com
To: rdk@clihouston.com
Subject: Re: Electrochemical Noise - Data Analysis Question
Date: Thu, 25 Sep 1997 22:57:14 GMTNoise specs on most any electronic device are given in v^2/Hz. If,this noise density is constant in frequency, the integral is easy; just multiply the constant spectral power density (in v^2/Hz) by the
bandwidth (Hz) and you get v^2. The square root of this is the expected rms noise voltage. Remember, that if you are looking at a long data trace, rms is approximately 1/5 the peak to peak noise level. An example: a typical low noise amp has internal noise density which, above 100Hz is approx. constant at 4 nV/Root Hz (or it could be stated as 16 nV^2/Hz). What is the total noise level in the audio band from
100Hz to 10KHz? I would just use the first number and multiply by the square root of the bandwidth: Vrms= 4E-9 V * Sqrt(E4) = 4E-7V = 0.4 microvolts, rms.
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Luis
unregistered
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posted 09-10-1997 06:37 PM
Dear Netters,I am learning about the use of electrochemical noise and during the data analysis I found that the units of the PSD in my software give me, for example, V^2. However a lot of reports present something like V^2/Hz. So in order to compare my results I would like any information or comments that help me to make an suitable correction to transform V^2 to V^2/Hz. Thanks in advance for your help. Sincerely, Luis
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